![]() I thought that Vivaldi should open with driver."From this update onwards, users will be able to browse smoothly all those websites that claim to be incompatible with Vivaldi," Vivaldi said in a blog post Thursday about the release of the new Vivaldi 29 that makes the change. : Message: Can not connect to the Service C:\Users\Negozio\AppData\Local\Vivaldi\Application\vivaldi.exe Raise WebDriverException("Can not connect to the Service %s" % self.path) Super(WebDriver, self)._init_(DesiredCapabilities.CHROME, "goog",įile "C:\Program Files\Python310\lib\site-packages\selenium\webdriver\chromium\webdriver.py", line 90, in _init_įile "C:\Program Files\Python310\lib\site-packages\selenium\webdriver\common\service.py", line 105, in start Finally I get this error: Traceback (most recent call last):įile "C:\Users\Negozio\Dropbox\D.Apps\Negozio\Conta\test.py", line 7, in įile "C:\Program Files\Python310\lib\site-packages\selenium\webdriver\chrome\webdriver.py", line 70, in _init_ The last line opens a new (unwanted) window of Vivaldi, which baffles me because I thought it should only declare a variable, and then nothing happens for some minutes. ![]() S = Service(rf"C:\Users\\AppData\Local\Vivaldi\Application\vivaldi.exe") This post asks how to open Vivaldi, and my script does it, but not when/how it's supposed to do it: from selenium import webdriverįrom import Service ![]() I want to manage the tabs of Vivaldi (Windows) using Python: get URLs, focus a specific tab, open, close, reload. ![]()
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